C program to check Armstrong number
C program to check Armstrong number : If number is equal to sum of all digits where each digit is raise to the count of digits then it is Armstrong number e.g. 153, 370, 371.
Let’s take 371
total digits is 371 (n) = 3
then 33 x 73 x 13 = 371
#include <stdio.h>
#include <math.h>
void isArmstrong(int n)
{
int a = n, b = n, len = 0, rsl = 0, rem;
while(b!=0)
{
len++;
b/=10;
}
while(a!=0)
{
rem = a%10;
rsl += pow(rem,len);
a /= 10;
}
if(rsl == n)
{
printf("Yes!!! It is an Armstrong number");
}
else
{
printf("No!!! It is not an Armstrong number");
}
}
//itvoyagers.in
int main ()
{
int x;
printf("Enter any number : ");
scanf("%d",&x);
isArmstrong(x);
return 0;
}
Output :
Enter any number : 371
Yes!!! It is an Armstrong number
———————————–
Enter any number : 1634
Yes!!! It is an Armstrong number
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