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C program for leap year
C program to check leap year :
We know that there are 365 day in a year but it is wrong. in one year there are 365.25 days. Hence every 4 year we have one extra day.
We have to use simple mathematics logic to solve this problem.
If year is divided by 4 then it is leap year.
If year is divided by 4 and not by 100 then it is leap year.
If year in not divisible by 4 then it is not a leap year.
If year is divisible by 4 and 100 then it must be divisible by 400 otherwise it is not a leap year.
#include<stdio.h>
int main()
{
int year;
printf("Enter year : ");
scanf("%d",&year);
if(year % 4 == 0)
{
if( year % 100 == 0)
{
if ( year % 400 == 0)
{
printf("%d is a leap year", year);
}
else
{
printf("%d is not a leap year", year);
}
}
else
{
printf("%d is a leap year", year);
}
}
else
{
printf("%d is not a leap year", year);
}
return 0;
}
Output :
Enter year : 2006
2006 is not a leap year
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